force-dat
| kgf·cm | N·m (approx) |
|---|---|
| 1 | 0.0981 |
| 2 | 0.1962 |
| 3 | 0.2943 |
| 4 | 0.3924 |
| 5 | 0.4905 |
| 6 | 0.5886 |
| 7 | 0.6867 |
| 8 | 0.7848 |
| 9 | 0.8829 |
| 10 | 0.981 |
| 15 | 1.4715 |
| 20 | 1.962 |
| 25 | 2.4525 |
| 30 | 2.943 |
| 50 | 4.905 |
| 100 | 9.81 |
Formula: N·m = kgf·cm × 0.09807
Torque to Lift a 10 kg Bottle by Hand
Given:
- Mass of bottle: 10 kg
- Gravity: 9.8 m/s²
- Force needed: F = m × g = 10 × 9.8 = 98 N
- Lever arm (distance from shoulder joint to hand): r = 0.3 m
Torque Formula:
T = F * r
Calculation:
T = 98 \, N * 0.3 \, m = 29.4 \, N·m
Result:
- Torque required: ≈ 29.4 N·m
Note:
For a longer lever arm (e.g., 0.5 m):
T = 98 * 0.5 = 49 N·m
- Torque depends on the pivot point; if lifting straight up without rotation, torque is less relevant.