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Tech-dat/power-dat/battery-dat/battery-capacity-dat/battery-capacity-dat.md
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| 1 | + |
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| 2 | +# battery-capacity-dat |
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| 3 | + |
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| 4 | + |
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| 5 | +## Car Sedan Lead-Acid battery |
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| 6 | + |
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| 7 | +- [[lead-acid-battery-dat]] |
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| 8 | + |
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| 9 | +- Typical Voltage (V): 12 V |
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| 10 | +- Typical Capacity Range (Ah): 40 Ah to 70 Ah |
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| 11 | + |
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| 12 | +Calculating Energy (Wh) = Voltage (V) × Capacity (Ah) |
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| 13 | + |
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| 14 | +- Minimum Energy: 12 V × 40 Ah = 480 Wh |
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| 15 | +- Maximum Energy: 12 V × 70 Ah = 840 Wh |
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| 16 | + |
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| 17 | +So, the energy stored in a typical car lead-acid battery is usually between 480 Wh and 840 Wh. |
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| 18 | + |
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| 19 | +## 20000 mAh * 3.7V |
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| 20 | + |
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| 21 | +Energy (Wh) = 20 Ah × 3.7 V = 74 Wh |
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| 22 | + |
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| 23 | +## 2.6Ah * 12V |
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| 24 | + |
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| 25 | +Energy (Wh) = 2.6 Ah × 12 V = 31.2 Wh |
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| 26 | + |
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| 27 | +## 1000 Wh |
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| 28 | + |
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| 29 | +1000 watt-hours (Wh) == 1 度 |
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| 30 | + |
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| 31 | +Runtime = 1000 Wh / 5V * 1A = 1000 Wh / 5W = 200 hours |
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| 32 | + |
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| 33 | +## quick calculation |
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| 34 | + |
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| 35 | +2000 mAh = 2 Ah |
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| 36 | +Runtime ≈ (2 Ah * 3.7 V * 0.85) / (1 A * 5 V) ≈ 1.26 hours |
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| 37 | + |
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| 38 | +for 20000 mAh, == 12.6 hours |
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| 39 | + |
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| 40 | +## Calculating Runtime for a 2000mAh Power Bank Supplying a 1A @ 5V Device |
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| 41 | + |
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| 42 | +Here's a breakdown of how to estimate the runtime: |
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| 43 | + |
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| 44 | +### 1. Power Bank Energy |
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| 45 | + |
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| 46 | +* **Capacity:** 2000 mAh (milliampere-hours) = 2 Ah (ampere-hours) |
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| 47 | +* **Nominal Voltage:** 3.7 V (typical for lithium-ion/polymer batteries) |
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| 48 | +* **Total Energy (Watt-hours, Wh):** Capacity (Ah) × Voltage (V) |
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| 49 | + * `2 Ah * 3.7 V = 7.4 Wh` |
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| 50 | + |
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| 51 | +### 2. Device Power Consumption |
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| 52 | + |
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| 53 | +* **Current:** 1 A (ampere) |
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| 54 | +* **Voltage:** 5 V (standard USB output) |
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| 55 | +* **Power Needed (Watts, W):** Current (A) × Voltage (V) |
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| 56 | + * `1 A * 5 V = 5 W` |
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| 57 | + |
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| 58 | +### 3. Efficiency Consideration |
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| 59 | + |
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| 60 | +Power banks are not 100% efficient when converting their internal battery voltage (3.7V) to the required 5V output. Energy is lost, primarily as heat, during this conversion. |
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| 61 | +* **Estimated Efficiency:** Let's assume an average efficiency of **85%** (or 0.85). This can vary between 80% and 95% depending on the quality of the power bank circuitry. |
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| 62 | + |
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| 63 | +### 4. Effective Energy Available |
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| 64 | + |
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| 65 | +This is the amount of the power bank's stored energy that can actually be delivered to the device after accounting for conversion losses. |
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| 66 | +* **Effective Energy:** Total Energy (Wh) × Efficiency |
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| 67 | + * `7.4 Wh * 0.85 ≈ 6.29 Wh` |
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| 68 | + |
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| 69 | +### 5. Calculate Runtime |
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| 70 | + |
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| 71 | +* **Runtime (hours):** Effective Energy Available (Wh) / Device Power Consumption (W) |
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| 72 | + * `6.29 Wh / 5 W ≈ 1.26 hours` |
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| 73 | + |
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| 74 | +### Conclusion |
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| 75 | + |
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| 76 | +A 2000mAh, 3.7V power bank can theoretically supply a device drawing 1A at 5V for approximately **1.26 hours**, or about **1 hour and 15 minutes**. |
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| 77 | + |
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| 78 | +**Disclaimer:** This is an estimate. Actual runtime depends on factors such as: |
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| 79 | +* The precise efficiency of the specific power bank. |
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| 80 | +* The age and health of the battery cells. |
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| 81 | +* The quality of the charging cable (resistance losses). |
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| 82 | +* Ambient temperature. |
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| 83 | +* Whether the device's power draw is constant or fluctuates. |
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| 84 | + |
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| 85 | + |
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| 86 | +## ref |
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| 87 | + |
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| 88 | +- [[Lead-acid-battery-dat]] |
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Tech-dat/tech-dat.md
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| 44 | 44 | |
| 45 | 45 | - [[RF-DAT]] |
| 46 | 46 | |
| 47 | -- [[LTE.-datmd]] - [[POE-dat]] - [[low-power-test-dat]] - [[M2M-interface]] |
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| 47 | +- [[LTE-dat]] - [[POE-dat]] - [[low-power-test-dat]] - [[M2M-interface]] |
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| 48 | 48 | |
| 49 | 49 | - [[bluetooth-dat]] |
| 50 | 50 | |
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| 52 | 52 | |
| 53 | 53 | ### Power |
| 54 | 54 | |
| 55 | -- [[power-dat]] |
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| 55 | +- [[power-dat]] - [[battery-dat]] |
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| 56 | 56 | |
| 57 | 57 | ### Interactive |
| 58 | 58 |